6x=2x^2/3

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Solution for 6x=2x^2/3 equation:



6x=2x^2/3
We move all terms to the left:
6x-(2x^2/3)=0
We get rid of parentheses
-2x^2/3+6x=0
We multiply all the terms by the denominator
-2x^2+6x*3=0
Wy multiply elements
-2x^2+18x=0
a = -2; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-2)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-2}=\frac{-36}{-4} =+9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-2}=\frac{0}{-4} =0 $

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